Send multipart form-data with cURL in Java

Paste a curl command that sends multipart form-data and get idiomatic Java code. We pick the right serialization for OkHttp and set the correct Content-Type.

Quick answer

To convert a cURL command to Java, paste it into the Toolpaper workbench below. It parses the command in your browser and emits idiomatic Java code — headers, query string, request body, authentication (Bearer, Basic, API key), and cookies are all wired up automatically. No data is uploaded; conversion is fully client-side.

Prefer a different target? See the full cURL to Java reference, or jump to the same guide in JavaScript, Node.js, or Python.

InputcURL command
MethodPOST·Headers0·Body—·Form2 fields· Chars 100
OutputJVM · OkHttp(modern JVM)
import java.io.File;
import okhttp3.MediaType;
import okhttp3.MultipartBody;
import okhttp3.OkHttpClient;
import okhttp3.Request;
import okhttp3.RequestBody;
import okhttp3.Response;

public class Main {
  public static void main(String[] args) throws Exception {
    OkHttpClient.Builder clientBuilder = new OkHttpClient.Builder();
    clientBuilder.followRedirects(false).followSslRedirects(false);
    OkHttpClient client = clientBuilder.build();
    MultipartBody.Builder mp = new MultipartBody.Builder().setType(MultipartBody.FORM);
    mp.addFormDataPart("file", "/path/to/photo.png", RequestBody.create(new File("/path/to/photo.png"), MediaType.parse("application/octet-stream")));
    mp.addFormDataPart("caption", "Hello");
    RequestBody body = mp.build();
    Request.Builder rb = new Request.Builder().url("https://api.example.com/upload");
    rb.method("POST", body);
    try (Response response = client.newCall(rb.build()).execute()) {
      System.out.println(response.body().string());
    }
  }
}
Inspect

Example

A representative curl command for this scenario. Paste your own above to convert an exact match.

curl input
curl -X POST https://api.example.com/upload \
  -F "file=@/path/to/photo.png" \
  -F "caption=Hello"

Implementation notes

  • Content-Type is detected from -H headers first, then inferred from the body shape when the header is missing.
  • Each -F flag becomes a distinct part; file@ paths are surfaced as OkHttp file handles so the multipart boundary stays valid.
  • Charset directives on Content-Type (e.g. application/json; charset=utf-8) survive the round trip.

Common mistakes

  • Setting Content-Type manually and then also using OkHttp's helper — you end up with duplicate headers or the wrong one wins.
  • Forgetting @ in -F "file=@upload.png" — without it curl sends the literal string, not the file. The generator flags this.
  • Trusting the browser DevTools "Copy as cURL" to preserve charset — it often drops it. Clean panel restores common defaults.

Common questions

How is multipart form-data encoded in the generated Java?
-F flags translate to multipart form-data with proper boundary handling — files={...} in Python, MultipartFormDataContent in C#, MultipartBody.Part in Java/Kotlin.
Does it preserve Content-Type?
Yes. The Content-Type header is honored and matched against the body so serialization stays consistent.
Is anything uploaded?
No. Parsing and generation happen entirely in your browser.

More payload types in Java

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Full Java reference on the cURL to Java hub, or open the main converter for all 18 targets.